the angle between the lines 2x=3y=-z and 6x=-y=-4z is|Write the angle between the lines 2x = 3y = : Bacolod Mathematics. Distinguish Acute Angle Bisectors and Obtuse Angle Bisectors. The angle bet. Question. The angle between the lines 2x= 3y= −z and 6x= −y= −4z is. A. 0∘. B. . Reset Password. Enter the username or e-mail you used in your profile. A password reset link will be sent to you by email.
the angle between the lines 2x=3y=-z and 6x=-y=-4z is,Mathematics. Distinguish Acute Angle Bisectors and Obtuse Angle Bisectors. The angle bet. Question. The angle between the lines 2x= 3y= −z and 6x= −y= −4z is. A. 0∘. B. .
Solution. The equations of the given lines can be re-written as x 3 = y 2 = z − 6 and x 2 = y − 12 = z − 3. We know that angle between the lines x − x 1 a 1 = y − y 1 b 1 = z − z 1 c 1 . The angle between the lines 2x = 3y = – z and 6x = -y = -4z is:A.0°B.90°C.45°D.30°. Ans: Hint: We will simplify the given equation of lines in the .
Solution. 2x = 3y = -z. x 3 = y 2 = Z - 6. and 6x = -y = -4z. cos θ = | a 1 a 2 + b 1 b 2 + c 1 c 2 a 1 2 + b |. = | 3 ( 4) + 2 ( - 24) + ( - 6) - 6 ( 3 2 + 2 2 + 6 2). ( 4 2 + 24 2 + 6 2) |. = | 12 - .
1 Answer. votes. answered Mar 19, 2021 by MukeshKumar (30.9k points) selected Mar 19, 2021 by Rupa01. Best answer. Given lines are. 2x = 3y = - z and 6x = - .
Question. The angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z is. A. 30 o. B. 45 o. C. 90 o. D. 0 o. Solution. Verified by Toppr. Correct option is C. 90 o. Was this .Solution. Verified by Toppr. Was this answer helpful? 0. Similar Questions. Q 1. Find the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. View Solution. Q 2. Angle .Find the angle between the lines 2x=3y=-z and 6x =-y=-4z. If a line makes angles α, β and γ with the axes respectively, then cos 2 α + cos 2 β + cos 2 γ = The equation of a line is .Write the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. The value of m for which the straight lines 3x – 2y + z + 3 = 0 = 4x – 3y + 4z + 1 are parallel to the plane 2x – y + mz = 2 is (a) 6 asked Jan 13, 2020 in Three-dimensional geometry by Nakul01 ( 36.4k points)Angle between the lines 2 x = 3 y = − z, 6 x = − y = − 4 z is 90 Since a 1 a 2 + b 1 b 2 + c 1 c 2 = 0. where a 1 = 1 2 , a 2 = 1 6 , b 1 = 1 3 , b 2 = − 1 , c 1 = − 1 , c 2 = − 1 4Write the angle between the lines 2x = 3y = The angle between the lines 2x=3y=−z and 6x=−y =−4z is. 11 mins ago. Discuss this question LIVE. Text solution Verified. (d) Given, equation of lines can be rewritten as. 1/2x = 1/3y = −1z. and 1/6x = −1y = −1/4z. ∴ cosθ = a12+b12+c12 a22+b22+c22a1a2+b1b2+c1c2. = 41+91+1 361+1+16121×61+31×(−1)−1×(−41)
Write the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines 2 x 3 y frac 3.the angle between the lines 2x=3y=-z and 6x=-y=-4z is Write the angle between the lines 2x = 3y = Find the angle between the lines $$2x = 3y = -z$$ and $$6x = -y = -4z$$. View Solution. Q3. Find the angle between the lines 2 x = 3 y =-z and 6 x =-y =-4 z. [CBSE 2015] View Solution. Q4. Write the angle between the lines $$2x = 3y = -z$$ and $$6x = -y = -4z$$. View Solution. Q5. The angle between the lines $$2x=3y=-z$$ and $$6x=-y=-4z$$ is?Find the angle between the two lines `2x = 3y = -z and 6x =-y = -4z` Find the angle between the lines whose direction cosines are given by the equations: 3l + m + 5n = 0 and 6mn – 2nl + 5lm = 0. Find the angle between the lines whose direction cosines are given by the equations l + m + n = 0, l 2 + m 2 – n 2 = 0.Angle between the lines 2x = 3y =−z and 6x =−y =−4z is. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines 2x3yz and 6xy4z is 2.KEAM 2015: The angle between the lines 2x=3y=-z and 6x=-y=-4z is (A) (π/6) (B) (π/4) (C) (π/3) (D) (π/2) (E) (2π/3). Check Answer and Solution fothe angle between the lines 2x=3y=-z and 6x=-y=-4z isFind the angle between the lines 2x=3y=-z and 6x =-y=-4z. If a line makes angles α, β and γ with the axes respectively, then cos 2 α + cos 2 β + cos 2 γ =. The equation of a line is 2x -2 = 3y +1 = 6z -2 find the direction ratios and also find the vector equation of the line.
Find the angle between the lines 2x = 3y = -z and 6x = -y = -4z See answers Advertisement Advertisement shadowsabers03 shadowsabers03 Consider the line, . This implies the direction ratios are perpendicular to each other, so are the lines and . Hence the angle between the lines is 90 .
The direction ratios of the line x – y + z – 5 = 0 = x – 3y – 6 are proportional to A. 3, 1, –2 B. 2, –4, 1 asked May 28, 2021 in Straight Lines by Aeny ( 45.1k points) straight line in space
Q. The angle between the lines 2x=3y=−z and 6x=−y=−4z is. Q. The angle between the lines 2x=3y=−zand6x=−y=−4z is. Q. The angle between the line 2x=3y=−z and 6x=−y=−4z is. Q. Find the angle between the lines 2 x = 3 y = - z and 6 x = - y = - . The angle between the lines 2x = 3y = – z and 6x = -y = -4z is: A.0° B.90° C.45° D.30° - Brainly.in. profile. banikoul9052. Writes that since both the lines intersect at the origin, the shortest distance between the two lines is 0 units. Given below are two lines L1 and L2: L1: 2x = 3y = -z L2: 6x = -y = -4z i . two lines. ii) Find the shortest distance between the two lines.
The angle between the line \[2x = 3y = - z\] and \[6x = - y = - 4z\] is A. \[90^\circ \] B. \[0^\circ \] C. \[30^\circ \] D. \[45^\circ \]The angle between the lines 2x = 3y= −zand 6x = −y = −4z is. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines2x3yzand6xy4zis.The angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z is. View Solution. Q3. Find the angle between the lines 2x=3y =-z and 6x=-y=-4z. View Solution. Q4.
The angle between the lines represented by the equation (x 2 + y 2) s i n θ + 2 x y = 0 is. View Solution. Q5. The straight lines joining the origin to the points of intersection of the line 2x + y = 1 and curve 3 x 2 + 4 x y .
the angle between the lines 2x=3y=-z and 6x=-y=-4z is|Write the angle between the lines 2x = 3y =
PH0 · Write the angle between the lines 2x = 3y =
PH1 · Write the Angle Between the Lines 2x = 3y = −Z and 6x = −Y
PH2 · The angle between the lines 2x=3y=
PH3 · The angle between the lines 2x = 3y = – z and 6x =
PH4 · The angle between the lines 2x = 3y = z and 6x = y= 4z is
PH5 · Find the angle between the two lines `2x = 3y =
PH6 · Find the angle between the lines 2x = 3y = – z and 6x = – y = – 4z
PH7 · Find the angle between the lines 2x = 3y =
PH8 · Find the Angle Between the Lines 2x=3y=